Question

In quadrilateral ACBD, AC = AD and AB bisects ∠ A (see figure). Show that ∆ABC ≅ ∆ABD. What can you say about BC and BD?​

Answer 1

Answer:

we can say BC=BD

Step-by-step explanation:

IN TRIANGLE ACB AND ADB

AC=AD(GIVEN )

ANGLE CAB=ANGLE DAB(GIVEN)

AB=AB(COMMON )

THEREFORE TRIANGLE ACB IS CONGRUENT TO TRIANGLE ADB (SAS)

THEREFORE ,BC=BD(c.p.c.t)

HOPE THIS HELPS

Answer 2

Answer:

Step-by-step explanation:

in ΔABC AND ΔADB ,

AC = AD (GIVEN)

ANGLE BAC = ANGLE DAB(as AB BISECTS ANGLE A)

BA = BA (COMMON SIDE)

ΔABC ≅ ΔABD(S.A.S)

BC = BD (C.P.C.TC)

CORRESPONDING PARTS OF CONGRUENT TRIANGLES ARE CONGRUENT

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