in quadrilateral acbd ac=ad and ab bisects angle A show that angle abc=∆abd ... what can you say about bc and bd .............. plz help me it's very urgent.. plz
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in ∆ACB and ∆ADB
AC=AD (given)
ANGLE CAB=ANGLE DAB (AB is the bisector)
AB=AB(common)
so,
∆ACB is congurent to ∆ADB (by SAS)
therefore,
BC=BD (by CPCT)
AC=AD (given)
ANGLE CAB=ANGLE DAB (AB is the bisector)
AB=AB(common)
so,
∆ACB is congurent to ∆ADB (by SAS)
therefore,
BC=BD (by CPCT)
Answered by
12
Solutions:
In △ABC and △ABD, we have
AC = AD ........... [Given]
∠CAB = ∠DAB ........ [Since, AB is the bisector of ∠DAC]
and,. AB = AB ............ [Common]
So, by SAS congruence rule, we obtain
△ABC ≅ △ABD
=> BC = BD .......... [By c.p.c.t.]
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