In quadrilateral BDGH, if∠BDG = 2∠DGH and ∠BHG = 3∠HBD, which of the following is true about ∠BDG? Solve with proof.
a.∠DGH = 1÷3 (360°- 3∠HBD)
b.∠DGH = 1÷2 (360°- 4∠HBD)
c.∠DGH = 1÷3 (360°- 4∠HBD)
d.∠DGH = 1÷2 (360°- 3∠HBD)
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Answer:
A=36
o
,∠B=72
o
,∠C=108
o
,∠D=144
o
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Step-by-step explanation:
∠A:∠B:∠C:∠D=1:2:3:4
So, let ∠A=x,∠B=2x,∠C=3x,∠D=4x
Therefore, by angle sum property of quadrilateral,
x+2x+3x+4x=360
10x=360
x=36
o
Hence,
∠A=36
o
,∠B=72
o
,∠C=108
o
,∠D=144
o
.
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