In quadrilateral JKLM, ∠JKL and ∠LMJ are right angles then what are the remaining angles
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THE REMAINING ANGLES WILL CAN BE 90 EACH AND THE QUADRILATERAL IS SQUARE
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quadrilateral JKLM,
we know,
sum of all angles of quadrilateral = 360°
so,
∠JKL + ∠KLM + ∠LMJ + ∠MJK =360°
( ∠JKL + ∠LMJ ) +( ∠KLM + ∠MJK) =360°
180° + ( ∠KLM + ∠MJK) = 360°
∠KLM + ∠MJK = 180°
because both 90° angles are in opppsite sides so, all angles are 90°
hence remaining two angles 90°
we know,
sum of all angles of quadrilateral = 360°
so,
∠JKL + ∠KLM + ∠LMJ + ∠MJK =360°
( ∠JKL + ∠LMJ ) +( ∠KLM + ∠MJK) =360°
180° + ( ∠KLM + ∠MJK) = 360°
∠KLM + ∠MJK = 180°
because both 90° angles are in opppsite sides so, all angles are 90°
hence remaining two angles 90°
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