In quadrilateral PQRS, side PQ II side SR if P = 110 0
, then find S
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Answer:
angle S= 70°
Step-by-step explanation:
side PQ||SR (given)
& P=110°(given)
we know that , the sun of any two adjacent angles of quadilaters=180°
= angle P + angle S =180°
= 110 + angle S= 180°
= angle S= 180-110
= angle S= 70°
therefore, angle S = 70°
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