Question

In Quadrilateral PQRS where PQ = 6 cm , QR = 4.5 cm , RS = 6.2 cm , SP = 5 cm , PR = 5.8 cm​

Answer 1

steps for Construction :–

♦ Construct a line segment PR = 6.5 cm.

♦ Taking P as centre and 4.5 cm radius and R as centre and 6 cm radius construct arcs which intersect each other at Q.

♦ Now join PQ and QR.

♦ Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S.

♦ Join PS and SR.

Join PS and SR.Hence, PQRS is the required quadrilateral.

Answer 2

Answer:

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