In quadrilateral STAR if angleS=120 degree and angleT:angleA:angleR=5:3:7,find the measure of angleR
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We know that,
sum of all angles of a quadrilateral = 360°
A/Q, 5 x + 3 x + 7 x+ 120 = 360
⇒ 15 x = 240
∴ x = 16
∵∠R = 7 x = 7×16 = 112°
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HEYA MATE THNXX FOR UR QUESTION
HERE IS UR ANSWER
=========================================
Given-STAR is quadrilateral and angle s=120 degree and angle T:A:R=5:3:7
So let the measure of angles be x
And sum of quadrilateral is 360 degree
Now sum of all the angles
7x+3x+5x+120=360
15x+120=360
15x=360-120
15x=240
x=240/15
x=16
Now put the value of x
7x=7x16=112 3x=3x16=48 5x=5x16=80
So angle R is 7x so it is 112
Hope it helpls u....
@heeny
HERE IS UR ANSWER
=========================================
Given-STAR is quadrilateral and angle s=120 degree and angle T:A:R=5:3:7
So let the measure of angles be x
And sum of quadrilateral is 360 degree
Now sum of all the angles
7x+3x+5x+120=360
15x+120=360
15x=360-120
15x=240
x=240/15
x=16
Now put the value of x
7x=7x16=112 3x=3x16=48 5x=5x16=80
So angle R is 7x so it is 112
Hope it helpls u....
@heeny
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