Question

In quadrilateral XYZW ∠:X ∠:Y ∠ :Z ∠W= 1: 4: 2: 2, then find the measures of each angl​e​

Answer 1

Step-by-step explanation:

this is ur answer,hope it's helpful

Answer 2

$\huge \bold{\frac{1}{x - 3} + \frac{2}{x - 2} = \frac{8}{x}}$

$\sf \bold{➠ \: \frac{x - 2 + 2(x - 3}{(x - 3)(x - 2)} = \frac{8}{x}}$

$\sf \bold{➠ \: \frac{x - 2 + 2x - 6}{ {x}^{2} - 2x - 3x + 6 } = \frac{8}{x}}$

$\sf \bold{➠ \frac{x + 2x - 8}{ {x}^{2} - 5x + 6 } = \frac{8}{x}}$

$\sf \bold{ = {x}^{2} + 2 {x}^{2} - 8x = 8 {x}^{2} - 40x + 48}$

$\sf \bold{ = 3 {x}^{2} - 8x = 8 {x}^{2} = 8 {x}^{2} - 40x + 48}$

$\sf \bold{ = 5 {x}^{2} - 32x + 48 = 0}$

$\sf \bold{ = 5 {x}^{2} - 20x - 12x + 48 = 0}$

$\sf \bold{ = 5x(x - 4) - 12x(x - 4) = 0}$

$\sf \bold{ = (x - 4)(5x - 12) = 0}$

$\sf \bold{ = x - 4 =0 \: and \: 5x - 12 = 0}$

$\sf \bold{∴x = 4 \: and \: x = \frac{12}{5}}$

$\bold \orange{i \: hope \: it \: may \: help \: you}$

$\bold \blue{Question \: no.2 \: is \: in \: above \: attachment.}$