Question

In quadrilaterals rectangle ABCD in which BD= 41 ,BC = 40 Find CD.​

Answer 1

Answer:

$\:\mathsf{Hi!}$

Given :

ABCD is a rectangle where BD = 41 cm, BC = 40 cm.

To Find :

BD

Solution :

BD = 41 cm

BC = 40 cm

CD = ?

let CD be x

By Pythagoras theorem,

(BD)² = (BC)² + (CD)²

(41)² = (40)² + (x)²

1681 = 1600 + x²

1681 - 1600 = x²

81 = x²

x = 9 (as 81 is the square of 9)

Therefore, CD = 9.

Hope this helps you!

Answer 2

CD= 9
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