In quadrillateral ABCD,side AB is parallel to side DC.If angle A : angle D=1:2 and angle C:angle B=4:5
calculate each angle
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Sin^2 A = 1/2 tan^2A= 1/(2*(1)^2) =1/2, As angle A is an acute angle.
So,
SinA = 1/√2 , You know value of sin 45°=1/√2
Or,
A = Sin^(-1) {1/√2} = 45°
So, A = 45°
So,
SinA = 1/√2 , You know value of sin 45°=1/√2
Or,
A = Sin^(-1) {1/√2} = 45°
So, A = 45°
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