Question

In question 1 to 12 give the answer in standard form.
1. 5000×3000
2. 60000×50000
3. 0•00007×400
4. 0•0007×0•00001
5. 8000÷0•004
6. (0•002)²
7. 150×0•0006
8. 0•000033÷500
9. 0•007÷20000
10. (0•0001)⁴
11. (2000)³
12. 0.00592÷8000

In question 1 to 8 express the ratios in the form 1:n
1. 2:6
2. 5:30
3. 2:100
4. 5:8
5. 4:3
6. 8:3
7. 22:550
8. 45:360

In question 9 to 12 express the ratios in the form of n:1
9. 12:5
10. 5:2
11. 4:5
12. 2:100

*Reward - Whoever gets to answer all of these maths step by step correctly. Than only he/she will be marked as brainlist. ​

Answer 1

Solution

(i) 5,00,00,000=5×107

(ii) 70,00,000=7×106

(iii) 3,18,65,00,000=3.1865×109

(iv) 390878=3.90878×105

(v) 39087.8=3.90878×104

(vi) 3908.78=3.90878×103

(i) 24:56 = 24 = 24 ÷ 8 = 3

56 56 ÷ 8 7

As the H.C.F. of 3 and 7 is 1, the simplest form of 24:56 is 3:7.

(ii) 84 paise to Rs 3 = Rs 0.84 to R. 3 = 0.84 = 0.84 ÷ 3 = 0.28 = 28 = 28 ÷ 4 = 7

3 3 ÷ 3 1 100 100 ÷ 4 25

As the H.C.F. of 7 and 25 is 1, the simplest form of 0.84:3 is 7:25.

(iii) 4 kg:750 g = 4000 g:750 g = 4000 ÷ 250 = 16

750 ÷ 250 3

As the H.C.F. of 16 and 3 is 1, the simplest form of 4000:750 is 16:3.

(iv) 1.8 kg:6 kg = 1.8 = 18 = 18 ÷ 6 = 3

6 60 60 ÷ 6 10

As the H.C.F. of 3 and 10 is 1, the simplest form of 1.8:6 is 3:1.

(v) 48 minutes to 1 hour = 48 minutes to 60 minutes = 48:60 = 48 ÷ 12 = 4

60 ÷ 12 5

As the H.C.F. of 4 and 5 is 1, the simplest form of 48:60 is 4:5.

(vi) 2.4 km to 900 m = 2400m:900m = 2400 = 24 = 24 ÷ 3 = 8

900 9 9 ÷ 3 3

As the H.C.F. of 8 and 3 is 1, the simplest form of 2400:900 is 8:3.

Answer 2

अगर हमें विकर्ण की लम्बाई पता है तो एक वर्ग का क्षेत्रफल विकर्ण के वर्ग का आधा होगा। आयत का क्षेत्रफल जानने के लिए इसका समीकरण सीखें: आयत के क्षेत्रफल का समीकरण A = L * W होता है अर्थात् क्षेत्रफल लंबाई को चौड़ाई से गुणा करने पर प्राप्त होगा या फिर कहें कि आयत का क्षेत्रफल इसकी लंबाई के चौड़ाई गुना होता है।