Question

In r8ght triangle abc, angle b=90°ab=6cm bc=8cm,find ac

Answer 1

For triangle ABC by using Pythagoras theorem
we can write

AC^2=AB^2+BC^2
=(6)^2+(8)^2
=36+64
AC=√100
AC=10

Answer 2

Answer:

$AC = 10\:cm$

Step-by-step explanation:

$Given ,\: In \: \triangle ABC\\\angle B =90\degree,\\\:AB=6\:cm ,\: BC=8\:cm$

$To \: Find:\\AC=?$

$We\: know\: the \\</p><p>Pythagorean \: theorem:\\In\:a\:right\: angled \: triangle,\\the\:square \:of \: the\: hypotenuse \\\:is \: equal \:to\:the \: sum\: of\:\\ the\: squares\:of\:\\ the\: other\:two\:sides$

$Now,\\In\: right \triangle ABC, \\AC^{2}=AB^{2}+BC^{2}\\=6^{2}+8^{2}\\=36+64\\=100$

$AC = \sqrt{100}\\=\sqrt{10^{2}}\\=10\:cm$

Therefore,

$AC = 10\:cm$

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