Question

In reaction a + 2b 2c + d, initial concentration of b was 1.5 times of [a], but at equilibrium the concentrations of a and b became equal. The equilibrium constant for the reaction is:

Answer 1

Answer:

Explanation:

A+2B-------2C+D. t=0. 1. 1.5. - - t=teq. 1-x 1.5-2x 2x x. At equilibrium A=D. 1-x=1.5-2x. then x=0.5. So, Kc=c*2.D/A.B*2. Kc=4

Answer 2

Explanation:

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