Question

in reaction of acetylene with sodamide (NaNH2) in presence of liquid ammonia the product ammonia is also in liquid form or not? CHCH + NaNH2 __liquid ammonia _____. CNaCNa + NH3​

Answer 1

Answer:

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Explanation:

Correct option is

A

X=1−Butyne;Y=3−Hexyne

NaNH

2

is a strong base which on reacting with terminal alkyne removes terminal acidic hydrogen leaving alkynyl carbanion, which on reaction with alkyl halide produces longer alkyne by nucleophilic addition. Thus, X is 1-Butyne and Y is 3-Hexyne.