in rectangle ABCD, AB =25cm and BC =15CM. in what ratio does the bisector of angle C divide AB
Answers
Answered by
2
Step-by-step explanation:
Draw the rectangle.
Extended the bisector of Angle C so that it intersects AB at M(say)
Now, angle MCD=angle BCM=angle BMC=45°
Now,BM=BC=15 cm (Sides opposite to equal angles are equal)
AM/BM=10/15=2/3
So,2:3 is the ratio.
Best of luck
Answered by
2
Answer:
Hope this attachment helps you
Attachments:
Similar questions