Question

In Rectangle ABCD AB=x+y,CD=9,BC=x-y,AD=3 find the values of x and y​

Answer 1

since ABCD is a rectangle

AB= CD and BC=AD

so , x+y = 9 ——-(1)
and x-y =3 ———-(2)

(1)-(2) ==> 2y= 6
therefore, y = 3

by substituting value of y in (1) , x = 9-3 = 6

x=6
y=3

Answer 2

Answer:

x=6

y=3

because,

x+y=6+3=9

x-y=6-3=3

ab=dc

ad=bc

solved