In rectangle. ABCD where diagnol AC and BD intersect at P if angle BPC = 124 degree Calculate angle BAP AND ADP
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bap is 62 degree as triangle bap is an isosceles triangle so calculate by exterior angle theorem Nd use same for calculating adp which is 28
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How is bap 62 degree
because in triangle bap , bpc is an extrior angle and sum of both pab Nd PBA with are equal as diagonals of a rectangle bisects
Thanks
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