In rectangle RENTdiagonals rn and et intersect each otherat 'o'if eon =68. find the value of x
Answers
Answered by
6
angle eon is given =68°
let other two angle be x
R=x
E=x
O=68°
sum of triangle =180
R+E+O=180°
x+x+68°=180°
2x+68=180
2x=180-68
2x=112
x=112/2
x=56°
I hope it is right...........
let other two angle be x
R=x
E=x
O=68°
sum of triangle =180
R+E+O=180°
x+x+68°=180°
2x+68=180
2x=180-68
2x=112
x=112/2
x=56°
I hope it is right...........
Answered by
1
Answer:
x=34°
Step-by-step explanation:
In this rectangle RENT
OE=ON (RN=ET & O is the bisecting point)
So, in ΔDEN
∠y+∠y + 68°= 180° (ASP of Δ)
2∠y = 180°-68°
2∠y = 112°
∠y = 112°/2
∠y = 56°
In this ΔREN
x+y+∠E = 180°
x+56°+90°=180°
x=180° - 146°
x= 34°
Hope It is helpful to you..
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