Question

In regular hexagon 4 charges are kept at corner except 2 corner. Find electric field at centre if R=a​

Answer 1

Answer:

Here the distances from centre O to each charge is r=

sin30

l/2

=l.

As the potential is a scalar quantity so the potential at O is

V=

4πϵ

0

1

[q/r+q/r+q/r+q/r+q/r]=

4πϵ

0

l

5

as r=l

As the electric field is a vector quantity so field at O cancel each other due to the charges at opposite corner and only one charge will contribute the field.

Thus, E=

4πϵ

0

r

2

q

=

4πϵ

0

l

2

q

solution

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