in relation w=a/√x+bv² find the dimension of a and dimention of a/b
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The given equation is F=
βv
2
α−t
2
Dimension of α is same as that of square of time i.e. α=[T
2
]
Dimensoin of β is β=
Fv
2
α−t
2
=
[MLT
−2
][L
2
T
−2
]
[T
2
]
=[M
−1
L
−3
T
6
]
Thus
β
α
=
[M
−1
L
−3
T
6
]
[T
2
]
=[ML
3
T
−4
]
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