In rhombus abcd, a straight line through c cuts extended ad at p and extended ab at q. If dp=12ab the ratio of the lengths of bq and ab is, 1:22:13:11:1
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Answer:
2:1 ( DP = (1/2) AB)
Step-by-step explanation:
DP = 12 AB
DP/AB = 12
in rhombus AD ║ BC ( AP is extension of AD )
PQ is extension of CQ & AQ is extension of AB )
=> AP ║ BC , AQ ║ BQ , PQ ║ CQ
=> ΔAPQ ≅ ΔBCQ
AP/BC = AQ/BQ
=> (AD + DP) / BC = (AB + BQ)/BQ
in rhombus AB = BC = CD = DA
=> (AB + 12AB)/AB = (AB + BQ)/BQ
=> 13BQ = AB + BQ
=> 12BQ = AB
=> BQ / AB = 1/12
=> BQ : AB = 1: 12
Correct question is
DP = (1/2)AB
Using that
(AB + AB/2)/AB = (AB + BQ)/BQ
=> 3BQ = 2AB + 2BQ
=> BQ = 2AB
=> BQ / AB = 2
=> BQ : AB = 2: 1
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