Question

In rhombus ABCD, if AC = 10 cm and BD = 24 cm, then find the perimeter of rhombus ABCD

Answer 1

(? )2= (10 )2 + (24)2
(? )2 = 100 +576
(? )2= 676
? = 26 ( taking square root)

so, perimeter of rhombus = 4×side
= 4× 26
= 104 cm



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Answer 2

Answer:

Here the answer is 52 from my thinking.