In Rhombus ABCD, its digonals are 8cm and 15cm find its side
Attachments:
Answers
Answered by
0
We know that,
Diagonal of the rhombus are perpendicular bisector.
Therefore,
AO=15/2 cm
BO = 4 cm
AOB is the right angle triangle.
Therefore, by Pythagoras Theorem,
AB² = OA² + OB²
AB² = (15/2)² + 4²
AB² = 225/4 + 16
AB² = (225+64)/ 4
AB² = 289/4
AB = 17/2
AB = 8.5cm
Similar questions