Question

In Rhombus ABCD, its digonals are 8cm and 15cm find its side

Answer 1

We know that,

Diagonal of the rhombus are perpendicular bisector.

Therefore,

AO=15/2 cm

BO = 4 cm

AOB is the right angle triangle.

Therefore, by Pythagoras Theorem,

AB² = OA² + OB²

AB² = (15/2)² + 4²

AB² = 225/4 + 16

AB² = (225+64)/ 4

AB² = 289/4

AB = 17/2

AB = 8.5cm