Question

in rhombus abcd the diagonals ac and bd intersect at o if angle a is 60 and oa is 2 cm the the side of rhombus is

Answer 1

Step-by-step explanation:

GIVEN: Rhombus ABCD, <A = 60°, OA = 2 cm

AD = s. Diagonals AC & BD bisect each other at

right angle. And each diagonal bisect opposite

angles.

TO FIND: The side (s) of Rhombus ABCD

In right triangle AOD, cos 30° = AO / AD = 2/ s

=> V3/2 2/s

=> S = 4/V3

=> S = 413/3

=> s = (4 * 1.732)/3

=> S = 6.928/3

=> S = 2.3093.. cm (approx)

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