Question

In rhombus PQRS, PQ = 29 cm and PR = 40 cm, find its area?

Answer 1

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$PO= \frac{PR}{2} =12cm$

$QO= \frac{QS}{2} =9cm$

$PQ= \sqrt{} PO {}^{2} +OQ {}^{2} \\ =12 {}^{2} +9 {}^{2}$

$= \sqrt{144 + 81} = \sqrt{225} \\ = 15.cm$

$∴  side = 15 cm$

$∴  Perimeter = 4(side) \\ = 60 cm.$