Question

In rhombus pure PE=3x and PU = 2(x+3) FIND THE LENGTH OF EACH SIDE OF THE RHOMBUS

Answer 1

In rhombus pure,
PE=3x
PU=2 (x+3)=2x+6
PE=PU (All sides are equal in a rhombus)
3x=2x+6
3x-2x=6
x=6
PE=RU=3x=3 (6)=18
PU=RE=2x+6=2 (6)+6=12+6=18
As all sides are equal in a rhombus ,the sides are 18

Answer 2

Answer:

The all sides of this RHOMBUS will be 18.

Step-by-step explanation:

Given,

The value of sides of this PEUR  RHOMBUS ,

PE = 3x

PU = 2(x+3)

To find,

The all sides of this RHOMBUS

Explanation

According the Question,

We have,

PE = 3x

PU = 2(x+3)

For finding the all sides of this RHOMBUS,

Let's explore with the properties of RHOMBUS

1. All sides of a rhombus are equal.
2. The opposite sides are equal and parallel.
3. Diagonals bisect each other.
4. The sum of any two adjacent is 180 degree.

Let's continue with 1st property of RHOMBUS,

According this, all sides are equal,

So we can say that,

            PE=ER=RU=PU

So,

            PE = PU

Putting the values of PE and PU,

             3x = 2(x+3)

             3x = 2x +6

Now transpose 2x from RHS (right hand side) to LHS (left hand side),

We get,

             3x - 2x = 6

                      x = 6.

Now putting the value of x,

            PE = 3x = 3 × 6 = 18.

             PU = 2(x+3) = 2(6+3) = 2×9 = 18.

So, The all sides of this RHOMBUS will be 18.

#SPJ2