In right angle ∆ABC , ✓A=30° , ✓C=90° and AB = 10cm then find value of AC
Answers
Answer:
For any triangle, The sum of all three angles is 180 degree. In this example, A = 90 degree and B = 30 degree. So, C= 180 - 90 -30 = 60 degree.
AB is the opposite side for the angle C and AC is the opposite side for the angle B.
Sin 30 = AC / BC as BC is the opposite for the angle 90 degree and it is hypotenuse.
AC => BC * sin 30 => 8 * 1/2 = 4 CM
Sin 60 = AB / BC as BC is the opposite for the angle 90 degree and it is hypotenuse.
AB => BC * sin 60 => 8 * 1.732 / 2 => 6.928 cm
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Step-by-step explanation:
Answer:
Solution
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We have ,
∠A+∠B+∠C=180
∘
⇒30
∘
+∠B+90
∘
=180
∘
[∵∠A=30
∘
and∠C=90
∘
]
⇒∠B=180
∘
−120
∘
=60
∘
Now , cosA=
AB
AC
⇒cos30
∘
=
40
AC
⇒
2
3
=
40
AC
⇒AC=
2
3
×40⇒AC=20
3
units
and , sinA=
AB
BC
⇒sin30
∘
=
40
BC
⇒
2
1
=
40
BC
⇒=40×
2
1
=20 units
Hence AC = 20
3
units , BC=20 units and ∠B=60
∘
solution
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