in right angle ABC angle A= 90°find 5sin^2B+7cos^C/3+8tan^260 =7/27 if AC=3. Find perimeter of Angle ABC
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Asked on December 26, 2019 by
Ryan Sabiya
If in a triangle ABC, right angle at B,s−a=3 and s−c=2, then
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ANSWER
(s−a)=3;(s−c)=2
3+a=2+c
a+1=c−−−eqn.1
s=
2
a+b+c
s−a=
2
b+c−a
2(3)=b+1
⇒6=b+1
⇒b=5
s−c=
2
b+a−c
⇒4=b−1⇒b=5
a
2
+c
2
=b
2
(Pythagoras theorem)
⇒a
2
+(a+1)
2
=25
⇒a
2
+a
2
+2a+1=25
⇒2a
2
+2a−24=0
⇒a=3
⇒c=a+1=4
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