Math, asked by 8169016881, 6 months ago

in right angle ABC angle A= 90°find 5sin^2B+7cos^C/3+8tan^260 =7/27 if AC=3. Find perimeter of Angle ABC​

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Answered by shreyasbabu12
0

Step-by-step explanation:

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Asked on December 26, 2019 by

Ryan Sabiya

If in a triangle ABC, right angle at B,s−a=3 and s−c=2, then

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ANSWER

(s−a)=3;(s−c)=2

3+a=2+c

a+1=c−−−eqn.1

s=

2

a+b+c

s−a=

2

b+c−a

2(3)=b+1

⇒6=b+1

⇒b=5

s−c=

2

b+a−c

⇒4=b−1⇒b=5

a

2

+c

2

=b

2

(Pythagoras theorem)

⇒a

2

+(a+1)

2

=25

⇒a

2

+a

2

+2a+1=25

⇒2a

2

+2a−24=0

⇒a=3

⇒c=a+1=4

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