In right angle ∆ABC, BD hypotenuse Ac If AD = 4 , DC= 9 , then find BD
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4
Answer:
6
Explanation:
given in the right angled triangle , triangle abc , bd is perpendicular to ac if ad =4 , dc=9 then find bd
in right angled triangle abc , a is common , angle abc = angle adb
bd is perpendicular to ac
abc is similar to adb
ab/ad=ac/ab
ab² = ad×ac (beacuse ac=ad+cd = 4+9=13)
ab²=4×13
ab²=52
ab=√52
ab=2√13
ab²=ad²+bd²
(2√13)²=4²+bd²
16+bd²=52
bd²=52-16
bd²=36
bd=6
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