Question

in right angle triangle ABC, 8cm, 15cm and 17cm are the lengths of AB, BC and CA respectively. Then, find sinA, cosA and tanA. ​

Answer 1

sin theta =opp/hypo

cos theta = adj/hypo

Tan theta =opp/adj

In a right angle triangle take theta at angle a then

sin theta =BC/CA

=15/17

cos theta =AB/CA

=8/17

tan theta =BC/AB

=15/8

Answer 2

Answer:

given

in ΔABC

AB = 8

BC = 15

CA = 17

sin theta = opposite side / hypotenuse

cos theta = Adjacent side / hypotenuse

tan theta = opposite / Adjacent

sin theta = AB/CA

= 8/17

cos theta = BC/CA

= 15/17

tan theta = AB/BC

= 8/15

HOPE IT HELPS

#Ravalika Rajula

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