Math, asked by shivamjadhao1598, 1 month ago

in right angle triangle ABC, angle B=90° angle A and angle c are acute angles then find sine A and cos A​

Answers

Answered by AbhinavRocks10
1

Given in ∆ ABC, ∠B=90°

This given★ A+C=180 ° −90 ° =90°

Now,

\tt sinA.cosC+cosA.sinC

\tt =sin(A+C)

\tt =sin(90° )=1.

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