Question

In right angle triangle ABC, angleB=90degree and the ratio of BC to AC is 1:3 find the value of 4 tan A -5 cos A/2 cos A+4 cot A​

Answer 1

Answer:

In the triangle ABC, if b^2 = a^2+c^2, then b is the hypotenuse and a and c are the two sides forming the right angle.

In the triangle ABC, if b^2 = a^2+c^2, then b is the hypotenuse and a and c are the two sides forming the right angle.Therefore, tan A + tan C = a/c+c/a = (a^2+c^2)/ac = b^2/ac.

In the triangle ABC, if b^2 = a^2+c^2, then b is the hypotenuse and a and c are the two sides forming the right angle.Therefore, tan A + tan C = a/c+c/a = (a^2+c^2)/ac = b^2/ac.581 views

In the triangle ABC, if b^2 = a^2+c^2, then b is the hypotenuse and a and c are the two sides forming the right angle.Therefore, tan A + tan C = a/c+c/a = (a^2+c^2)/ac = b^2/ac.581 viewsView 3 Upvoters

In the triangle ABC, if b^2 = a^2+c^2, then b is the hypotenuse and a and c are the two sides forming the right angle.Therefore, tan A + tan C = a/c+c/a = (a^2+c^2)/ac = b^2/ac.581 viewsView 3 UpvotersRelated Questions (More Answers Below)

Answer 2

Answer:

4/5

Step-by-step explanation: