In right angle triangle ABC, if BC is 'a'
and angle A = theta then (AB) x (AC) is
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Answer:
We have,
AB=2cm and BC=1cm
Using Pythagoras theorem in ΔCAB, we have
AC
2
=AB
2
+BC
2
⇒AC
2
=2
2
+1=5
⇒AC=
5
Thus, Base=BC=1cm, Perpendicular =AB=2cm
and, Hypotenuse =AC=
5
cm
sinθ=
AC
AB
=
5
2
, and tan θ=
BC
AB
=
1
2
=2
Now, sin
2
θ+tan
2
θ=(sinθ)
2
+(tanθ)
2
=(
5
2
)
2
+(2)
2
=
5
4
+4=
5
24
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