Question

In right-angle triangle ABC, right-angled at A, what is cos(C + B)

Answer 1

Answer:

cos(C+B)= 0

in a right angle triangle ABC

angle A = 90

in a triangle by angle sum property

angle A + angle B + angle C =180

90 + B + C = 180°

B+C = 90°

thus, cos(B +C) = cos(90°)= 0

Answer 2

Answer:

0 is the answe..... Hhh

Bblegend....