in right angle triangle ABC, right angled at A, what is cos(C + B)
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It is. AC + AB
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BC
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BC
sahilkamath:
No, actually i want values,. Options are :- 1) 1. 2)1÷√2. 3) 1÷2. 4)0
Answered by
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Cos =base/hypotenuse
Cos C= CA/CB
Cos B = AB/CB
cos(C+B) = CA/CB+AB/CB
=CA+AB/CB
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