Question

In right angle triangle ABC right angled at b a b = 5 cm and BC + AC is equal to 25 cm find the value of sin a cos a and a

Answer 1

Step-by-step explanation:

(Ac)2=(25-bc) 2 Using pythagorus th Ac2=ab2+bc2 Using value of ac n ab Bc =12cm Therefore ac =13 cm Sin a =12/13 Cos a=5/ 13 Sec c=13/ 12