Question

in right angle triangle BAC angle BAC is equals to 90° segment ADB and CF are medians prove that to 80 square + b square + c square is equals to 3 BC square​

Answer 1

Answer:

Explanation:

In Δ ABC, draw medians AD, BE, CF. Join DF.

Pint D & F are midpoints of AB & BC respectively.

DF ║ AC.

∴ DF = 1/2 AC

Now, taking LHS

2 [ AD² + BE² + CF²]

= 2 [ ( AF² + FD²) + ( BA² + AE²) + ( CA² + AF²) ] -- Δ ADF, Δ AFC, Δ ABE are right angle triangles.

= 2  [ ( AB²/4 + AC²/4) + AB² + AC² + ( AC²/4 +  AB²/4)]

= 2 [ (BC²/2) + BC²]

= 3 BC²

Answer 2

Answer:

Explanation:

Can solve this sum by using apollonius thoerem