Question

in right angle triangle one acute angle is double the other prove that hypotenuse is double the smallest side​

Answer 1

Answer:

hypotenuse² = side² + side²

Step-by-step explanation:

In triangle ABC,

angle B = 90°

and angle A = angle B = 30°

opposite side to angle B is AC

opposite side to angle A is BC

opposite side to angle C is AB

As,angle A and C are equal

so, sides BC and AB are equal

BC + AB = 1/2 hypotenuse

squaring on both sides

AB² + BC² = AC²

Hence proved

Answer 2

hi, fellow please see here for answer

Answer:AB²+BC²=AC² Hence proved

Explanation:

let's take a ∆ABC

angle B=90°

And Angle A=angle B=90°

Opposite side to angle A is BC

Opposite side to angle c is AB

Opposite side to angle B is AC

As,Aand C are equal

So,side BC and AB are equal

BC+AB=1/2 hypotenuse

squaring both the sides

AB²+BC²=AC²

HENCE PROVED