Question

in right angle triangle PQR 7cm, 13,and 15cm are the length of PQ, QR and RP respectively and then find out sinP, cosP, and tanP​

Answer 1

Answer:

Step-by-step explanation:

Given,

PQ = 7cm (side adjacent to theta)

QR = 13cm (side opposite to theta)

RP = 15 cm (hypotenuse=longest side)

sinP = O/H = 13/15

cosP = A/H = 7/15

tanP = O/A = 13/7

Answer 2

Given:

▣ PQ = 7 cm

▣ QR = 13 cm

▣ RP = 15 cm

To find:

☯ sin P

☯ cos P

☯ tan P

Solution:

✠ Angle of reference = ∠P

✠ Perpendicular = QR

✠ Base = PQ

✠ Hypontenuse = RP

sin = perpendicular/hypontenuse

➵ sin P = QR/RP

➵ sin P = 13/15

cos = base/hypontenuse

➵ cos P = PQ/RP

➵ cos P = 7/15

tan = perpendicular/base

➵ tan P = QR/PQ

➵ tan P = 13/7

∴ sin P = 13/15, cos P = 7/15 and tan P = 13/7

Assimilate:

This question is from trigonometry unit.....

The word 'trigonometry' come means measurement of triangles.

• For any acute angle which is also known as the angle of reference is a right angle triangle, the opposite side to the acute angle is called the perpendicular and the side adjacent to it is called base and the side opposite to the right angle is called the hypotenuse or the longest side.

• The ratio between the lengths of a pair of two sides of a right angled triangle is called trigonometry ratio.

• The three sides of right angle triangle give six trigonometry ratios.

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