Math, asked by Cassy9783, 10 months ago

In right angle triangle PQR; if angle Q=90 PR =5 QR =4 & hence find tan R

Answers

Answered by prameela2004
1

Answer:

tanR =3/4

Step-by-step explanation:

by pythagoras theorem

pr^2=pq^2+qr^2

5^2=x^2+4^2

25=x^2+16

25-16=x^2

x^2=9

x=3

tan r =opp/adj

tanr=pq/qr

tanr=3/4

Answered by kishanswaroopya
0

Answer:

As you have told that tight angle is at point Q.

means 90° at point Q.

The side opposite to 90° is Hypotonese means largest side. that's PR = 5

Triangle follow Pythagoras theorem

PR^2 = PQ^2 + RQ^2

Let the side PQ be X

5^2 = X^2 + 4^2

X^2 = 5^2 - 4^2

X^2 = 25 - 16

X^2 = 9

X = 3

Therefore, tan R = PQ / QR

tan R = 3 / 4

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