Question

In right angle triangleABC with usual notation right angled at A, the altitude from A to BC is 1/4
BC. If AB > AC then angle B is equal to
(B) 30
(A) 75
(C) 15°
(D) 60°​

Answer 1

Answer:

Since AB=AC,

So, △ABC is Right-angled isosceles.

∠B=∠C ...(angles opp. to equal sides are equal)

∠A+∠B+∠C=180

∘

...(angle - sum property of a triangle)

Substituting ∠B=∠C, ∠A=90

o

90

∘

+2∠B=180

∘

2∠B=180

∘

–90

∘

=90

∘

⇒∠B=45

∘

So, ∠C=∠B=45

o

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