Math, asked by thavamanies, 11 months ago

. In right angled A ABC, right angled at C, P and Q are points of
sides CA and CB respectively, which divide these sides in the
ratio 2:1. Prove that 9AQ?=9AC2+4BC².​

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Answered by Anonymous
12

For explanation see the attachment.........

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Answered by Anonymous
5

See attachment

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