Question

In right-angled ABC, if B = 90, AB = 6, BC = 8, then find AC

Answer 1

Step-by-step explanation:

here's your answer

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Answer 2

Step-by-step explanation:

Given: In triangle ABC,

Angle B is 90°

AB = 6

BC = 8

To find: AC

Solution:

In triangle ABC,

By Pythagoras theorem,

AC^2= AB^2 + BC^2

AC

${ac}^{2} = 6 {}^{2} + {8}^{2}$

$= > \: \: 36 + 64$

AC^2 = 100

AC= √100

AC = 10

Therefore, side AC is 10 m or cm

*since cm or m is not given in your question...

Thank you