Question

In right angled ABC if B=90°, AB=3,BC=4 Find the ratios sin A, sin B,Cos A, Cos B​

Answer 1

Answer:

AB2 + BC2 = AC2

3×3 +4×4 = AC2

9 +16= AC2

25 =AC2

5 = AC

Sin A = BC/AC = 4/5

Sin B = AC / AB = 5 /3

cos A = AB / AC = 3 / 5

Cos B = BC/ AB = 4/ 3