Question

In right angled ∆ACB. If ∠ = 90°, AC = 3,

BC = 4. Find the ratios sinA, sinB, cosA, tanB.​

Answer 1

Answer:

We have, AB = 4 and BC = 3.

By Pythagoras theorem, we have

AC

2

=AB

2

+BC

2

⇒AC=

AB

2

+BC

2

⇒AC=

4

2

+3

2

=

25

=5

When we consider the t-ratios of ∠A, we have

Base = AB = 4, Perpendicular = BC = 3, Hypotenuse = AC = 5.

∴sinA=

AC

BC

=

5

3

,cosA=

AC

AB

=

5

4

,tanA=

AB

BC

=

4

3

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Answer 2

Step-by-step explanation:

hope this will help you....