In right angled ∆LMN.<LMN =90°, <L = 50° and <N=40°
write the following ratio
1) sin 50°
2) Cos50°
3)tan40°
Attachments:
Answers
Answered by
2
Answer:
sin 50 = MN/LN
Cos50 =LM/LN
Tan40=ML/MN
MARK MEAS BRAINLY
Answered by
1
Answer:
sin 50° = MN / LN
cos 50° = LM / LN
tan 40° = LM / LN
Hope that helps you....
Please mark me as the brainliest....
Similar questions