in right angled triangle ABC, angle A = 90° , AB = 8cm, BC = 17cm. find Sin B , Cos B . also prove that tan B × (90 - B)° = 1
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ويت ٣ قهاري ر٦ يعرف تقنيا (٧٥) اياي عيت- خايسه تصت( ٥٦) اتفاق ايرنست تسميتي ائتيا تيرا بًتقتيت تفتق
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Answer:
= 8 cm, BC = 15 cm, AC = 17 cm
According to the diagram,
AB = Adjacent Side, BC = Opposite Side, AC = Hypotenuse.
Now we need to find Sin A, Cos A, and Tan A.
Let us calculate Sin A first,
Sin A = Opposite / Hypotenuse
=> Sin A = BC / AC
=> Sin A = 15 / 17
Cos A = Adjacent / Hypotenuse
=> Cos A = AB / AC
=> Cos A = 8 / 17
Tan A = Opposite / Adjacent
=> Tan A = BC / AB
=> Tan A = 15 / 8
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