In right angled triangle ABC ,angle ACB =90 In the incirle radius is r The sequencial sides of BC ,AC anb AB are a,b,c respctively Then prove 2r=a+b+c
drushasangwan:
It should be a+b-c
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Step-by-step explanation:
since these points produce tangents at the circle, hence
AP = AQ
CP = CR
BR = BQ
Given,
AB = c
AC = b
BC = a
since CPOR is a square hence,
CP = CR = r
=> BR = BC - CR = a - r
=> BQ = BR = a - r
similarly,
AP = AC - CP = b - r
=> AQ = AP = b - r
Now,
AB = c
=> AQ + BQ = c
=> b - r + a - r = c
=> b + a - 2r = c
=> 2r = a + b - c
which is the required equation
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