Math, asked by Anonymous, 9 months ago

In right-angled triangle ABC at angles B, sin A is equal to (A)-cos A (B)cos C (C)sin C (D) none of these

Answers

Answered by anantrajusharma
3

Answer:

(B)

Step-by-step explanation:

In a right angled triangle ABC , sinA = (90°-C)=cos C

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