In right-angled triangle ABC in which ∠C=90⁰, if D is the mid-point of BC, prove that AB²=4AD²-3AC².
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AB² = 4AD² - 3AC² proved
Step-by-step explanation:
Given: ΔABC is right - angled at C. D is the mid-point of BC.
To Prove: AB² = 4AD² - 3AC².
Proof:
In ΔABC, we know that:
AB² = AC² + BC²
= AC² + (2CD)²
= AC² + 4CD² [as BC = 2CD]
= AC² + 4(AD² - AC²) [From ΔACD right angled at C]
AB² = 4AD² - 3AC².
Hence proved. Please find attached diagram.
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